# include <stdio.h>
# include <math.h>
# include <float.h>
# include <limits.h>
# include <sys/time.h>

/*
 * Program: Stream
 * Programmer: Joe R. Zagar
 * Revision: 4.0-BETA, October 24, 1995
 * Original code developed by John D. McCalpin
 *
 * This program measures memory transfer rates in MB/s for simple 
 * computational kernels coded in C.  These numbers reveal the quality
 * of code generation for simple uncacheable kernels as well as showing
 * the cost of floating-point operations relative to memory accesses.
 *
 * INSTRUCTIONS:
 *
 *	1) Stream requires a good bit of memory to run.  Adjust the
 *          value of 'N' (below) to give a 'timing calibration' of 
 *          at least 20 clock-ticks.  This will provide rate estimates
 *          that should be good to about 5% precision.
 */

# define N 50000000	
# define NTIMES 1 
# define OFFSET 0	

/*
 *	3) Compile the code with full optimization.  Many compilers
 *	   generate unreasonably bad code before the optimizer tightens
 *	   things up.  If the results are unreasonably good, on the
 *	   other hand, the optimizer might be too smart for me!
 *
 *         Try compiling with:
 *               cc -O stream_d.c second_wall.c -o stream_d -lm
 *
 *         This is known to work on Cray, SGI, IBM, and Sun machines.
 *
 *
 *	4) Mail the results to mccalpin@cs.virginia.edu
 *	   Be sure to include:
 *		a) computer hardware model number and software revision
 *		b) the compiler flags
 *		c) all of the output from the test case.
 * Thanks!
 *
 */

# define HLINE "-------------------------------------------------------------\n"

# ifndef MIN
# define MIN(x,y) ((x)<(y)?(x):(y))
# endif
# ifndef MAX
# define MAX(x,y) ((x)>(y)?(x):(y))
# endif

static double	a[N+OFFSET],
		b[N+OFFSET],
		c[N+OFFSET];

static double	rmstime[4] = {0}, maxtime[4] = {0},
		mintime[4] = {FLT_MAX,FLT_MAX,FLT_MAX,FLT_MAX};

static char	*label[4] = {"Copy:      ", "Scale:     ",
    "Add:       ", "Triad:     "};

static double	bytes[4] = {
    2 * sizeof(double) * N,
    2 * sizeof(double) * N,
    3 * sizeof(double) * N,
    3 * sizeof(double) * N
    };

extern double mysecond();

int
main()
    {
    int			quantum, checktick();
    int			BytesPerWord;
    register int	j, k;
    double		scalar, t, times[4][NTIMES];

    /* --- SETUP --- determine precision and check timing --- */

    printf(HLINE);
    BytesPerWord = sizeof(double);
    printf("This system uses %d bytes per DOUBLE PRECISION word.\n",
	BytesPerWord);

    printf(HLINE);
    printf("Array size = %d, Offset = %d\n" , N, OFFSET);
    printf("Total memory required = %.1f MB.\n",
	(3 * N * BytesPerWord) / 1048576.0);
    printf("Each test is run %d times, but only\n", NTIMES);
    printf("the *best* time for each is used.\n");

    /* Get initial value for system clock. */
//#pragma omp parallel for
    for (j=0; j<N; j++) {
	a[j] = 1.0;
	b[j] = 2.0;
	c[j] = 0.0;
	}

    printf(HLINE);

    if  ( (quantum = checktick()) >= 1) 
	printf("Your clock granularity/precision appears to be "
	    "%d microseconds.\n", quantum);
    else
	printf("Your clock granularity appears to be "
	    "less than one microsecond.\n");

    t = mysecond();
#pragma omp parallel for
    for (j = 0; j < N; j++)
	a[j] = 2.0E0 * a[j];
    t = 1.0E6 * (mysecond() - t);

    printf("Each test below will take on the order"
	" of %d microseconds.\n", (int) t  );
    printf("   (= %d clock ticks)\n", (int) (t/quantum) );
    printf("Increase the size of the arrays if this shows that\n");
    printf("you are not getting at least 20 clock ticks per test.\n");

    printf(HLINE);

    printf("WARNING -- The above is only a rough guideline.\n");
    printf("For best results, please be sure you know the\n");
    printf("precision of your system timer.\n");
    printf(HLINE);
    
    /*	--- MAIN LOOP --- repeat test cases NTIMES times --- */

    scalar = 3.0;
    for (k=0; k<NTIMES; k++)
	{
	times[0][k] = mysecond();
#pragma omp parallel for
	for (j=0; j<N; j++)
	    c[j] = a[j];
	times[0][k] = mysecond() - times[0][k];
	
	times[1][k] = mysecond();
#pragma omp parallel for
	for (j=0; j<N; j++)
	    b[j] = scalar*c[j];
	times[1][k] = mysecond() - times[1][k];
	
	times[2][k] = mysecond();
#pragma omp parallel for
	for (j=0; j<N; j++)
	    c[j] = a[j]+b[j];
	times[2][k] = mysecond() - times[2][k];
	
	times[3][k] = mysecond();
#pragma omp parallel for
	for (j=0; j<N; j++)
	    a[j] = b[j]+scalar*c[j];
	times[3][k] = mysecond() - times[3][k];
	}
    
    /*	--- SUMMARY --- */

    for (k=0; k<NTIMES; k++)
	{
	for (j=0; j<4; j++)
	    {
	    rmstime[j] = rmstime[j] + (times[j][k] * times[j][k]);
	    mintime[j] = MIN(mintime[j], times[j][k]);
	    maxtime[j] = MAX(maxtime[j], times[j][k]);
	    }
	}
    
    printf("Function      Rate (MB/s)   RMS time     Min time     Max time\n");
    for (j=0; j<4; j++) {
	rmstime[j] = sqrt(rmstime[j]/(double)NTIMES);

	printf("%s%11.4f  %11.4f  %11.4f  %11.4f\n", label[j],
	       1.0E-06 * bytes[j]/mintime[j],
	       rmstime[j],
	       mintime[j],
	       maxtime[j]);
    }
    return 0;
}

# define	M	20

int
checktick()
    {
    int		i, minDelta, Delta;
    double	t1, t2, timesfound[M];

/*  Collect a sequence of M unique time values from the system. */

    for (i = 0; i < M; i++) {
	t1 = mysecond();
	while( ((t2=mysecond()) - t1) < 1.0E-6 )
	    ;
	timesfound[i] = t1 = t2;
	}

/*
 * Determine the minimum difference between these M values.
 * This result will be our estimate (in microseconds) for the
 * clock granularity.
 */

    minDelta = 1000000;
    for (i = 1; i < M; i++) {
	Delta = (int)( 1.0E6 * (timesfound[i]-timesfound[i-1]));
	minDelta = MIN(minDelta, MAX(Delta,0));
	}

   return(minDelta);
    }