''' Purpose: print contents of a user-indicated web page
'''

# get url link of interest
reply = input( "Enter url: " )

###############  BOILERPLATE TO GET CONTENTS OF WEB FILE ###############
#we've seen all of this before
# need help to get web data - so import the capability
from urllib.request import urlopen
#
# # clean up the reply
link = reply.strip()
#
# # get a connection to stream the web resource of interest
# stream = urllib.request.urlopen( link )
#
# # read stream to gets its encoded contents
# page = stream.read()
#
# # decode page into plain text form
# text = page.decode()
#print( text )
###############             END OF BOILERPLATE           ###############

# the above code is tedious, need a function to do take care this crud

import url #homemade module used to do all the streaming etc. for you
#typing the same four lines gets annoying so this saves us time
#please use this. It will save you time
text = url.get_contents( link )

# now let's get the lines that make up the text
print( 'text =' , text )

# split the text into a list of line
lines = text.split( "\n" )

#we can tell .split() to split on anything we want, in this case we telling it to split on new lines
# print the lines one by one

print( "lines" )
for line in lines :
    print( "line =", line )