def g( x ) :
    ''' Solves the uate.g() homework 24 problem description
    '''

    # General Accumulation Function For a List
    # accumulator = []
    # for ...
        # accumulator.append( ... )
    # return accumulator

    answer = []         # We want to build up a list of unique strings (accumulator)
    for element in x:   # Look at each element in x one by one
        # We don't want to add elements that are already in our answer list!
        if ( element not in answer ):   # If it's not already in our list of unique strings
            answer.append( element )    # Add the element to our answer!
    return answer



''' DO NOT MODIFY THE BELOW CODE ''''

if ( __name__ == '__main__' ) :
    import uate

    x1 = [ 0, 1, 2 ]
    x2 = [ 0, 4, 1, 2, 2, 1, 3, 6, 3, 3, 4 ]
    x3 = [ ]

    z1 = uate.g( x1 );   print( 'g( x1 ) =', z1 )
    z2 = uate.g( x2 );   print( 'g( x2 ) =', z2 )
    z3 = uate.g( x3 );   print( 'g( x3 ) =', z3 )