''' Purpose: consider string casing functions
'''

text = input( "Enter text: " )

text = text.lower() # Reassigns text to be the lowercase version of the original value of text

substring = input( "Enter substring: " )

substring = substring.lower() # Reassigns substring to be the lowercase version of the original value of substring

i = input( "Enter index: " )
i = int( i )

print()

# count occurrences of text
# NEW FUNCTION: count() -> s.count( substring we want to count ) -> gives you the number of times the
# substring occurs in the string (counts the thing in parentheses in the string s)
total = text.count( substring )

from_index_i_on = text.count( substring, i ) # You can also provide an optional index i
# that basically says that it will look for the substring starting from index i (including index i)

   #1   #2 #3    where 'an' occurs
# 'any bananas'
#  012345678910

# In the entire string, there are three occurences of 'an'
# From 7 onwards (including index 7), there is only 1 'an'

# The substring is case-sensitive!
# 'Any bananas'
#  ^ This 'An' is not 'an' so it doesn't count (not part of the count)

# How can we still find the right count even if it's different cases?
    # Make everything lowercase (all characters lowercase)
    # Count lowercase version of substring we want


print( "text.count( substring ) =", total, "       # count all" )
print( "text.count( substring,", i, ") =", from_index_i_on, "    # count starting from index", i )