''' Purpose: Experience the thrill of random generation and list examination

    Task: Prompt and get three integers s, n, and d from its user (in that
          order). Use integer s as a seed to the Python random number
          generator. Then print n octal digits (base 8 digits) line by
          line by line. Then print the number of generated occurrences of d.
          There should be no other output

    Checker:

'''

# needed module
import random

#####  Get the input 

reply = input( 'Enter three numbers: ' )

#####  Convert the input into the integers s, d, n   
s, n, d = reply.split()

s, n, d = int( s ), int( n ), int( d )


#####  Set the seed for generating random values 
random.seed( s )


#####  Generate and print n random octal numbers and along the way store them in a list
digit_list = []                  # start off with an empty list

# add n random 0, 1, 2, 3, 4, 5, 6, or 7's (i.e, octal digits) to numbers

for i in range( 0, n ) :   # i is the iterator, loop will repeat n times

    # each iteration want to add another digit to the list of digits

    next_digit = random.randrange( 0, 8 )   # get the next digit
    digit_list.append( next_digit )         # add the next digit to the end of the digit list

# when all done print our list of octal digits
print( digit_list )

# now we want to know the number of times digit d is in our list of digits
occurrences = digit_list.count( d )         # counts the number of d's in the digit list

print( occurrences )