''' Purpose: determine the length and number of vowels of a user-specified word
'''

# HELPFUL CONSTANT

VOWELS = 'aeiou'

# In our loop, v will be 'a' then next time 'e'
# then next time 'i' then next time 'o' then next time 'u'
# and then the loop is done because it has reached the
# end of the sequence!

# get the input
reply = input( 'Enter a word: ' )

# clean it up
# Remove all leading and trailing whitespace using .strip()!

s = reply.strip() # Call .strip() to remove leading and trailing
s = s.lower() # Makes the entire string lowercase

s = reply.strip().lower() # YOU CAN DO EVERYTHING AT ONCE TOO

# so that you can just count the lowercase vowels in VOWELS
# You could make VOWELS = 'aeiouAEIOU' but it's quicker to just
# make everything lowercase!
# .strip gets rid of whitespace! # "     nadia  " becomes "nadia"

# determine and report its length

n = len( s )

# determine and report the total of the number of occurrences of each of the vowels

# Store each count separately in five different variables and
# get the total

ca = s.count( "a" )
ce = s.count( "e" )
ci = s.count( "i" )
co = s.count( "o" )
cu = s.count( "u" )

total = ca + ce + ci + co + cu

# An alternate method would be to use a for loop to count!
# This is an accumulator way :)
# Initialize a total to 0

total = 0
for v in VOWELS: # 'aeiou' - v will change value from 'a' to 'e' to 'i' etc.
    c_v = s.count( v ) # This will count the # times vowel occurs
    # in the string for the current value of v!
    total = total + c_v # Take the total and keep adding
    # each count of the new vowel

print("Length", n )
print("Vowels:", total)

# You can also replace all the vowels in the original
# string with "" and then count the word after that
# as it would be only the remaining consonants. (this
# essentially gets rid of all the vowels in the original string
# and counts up the new string with just the consonants)