''' Purpose: use if-else statement
'''
# is the first value in the input text a vowel?

# define helpful constant
VOWELS = "aeiou"

# get input text and put into canonical form
text = input( 'Enter text: ' )

text = text.strip()

text = text.lower()   # lower because all of the characters in VOWELS is lowercase
                      # we want to evaluate whether the first character is a vowel regardless of case

# determine its first character
first_character = text[0]
print( 'first_character =', first_character )

# determine whether first character is a vowel --> need if/else statement?
# look in first char --> look in VOWELS --> if first char in VOWELS
#   if it is in VOWELS (then first char is a vowel): then print yes?
#   otherwise (not in VOWELS) : then print no?

if ( first_character in VOWELS ):
    # first_character IS a vowel

    # first_character is SINGLE character
    # VOWELS is a STRING of length 5 (5 characters)
    # therefore, first_character is NEVER == to VOWELS
    # we want to know whether first_character is IN VOWELS
    # in: take a substring and check whether that substring/char is in the second string

    print( 'yes' )
# print( 'almost done' )
else:
    # first_character is NOT a vowel
    print( 'no' )

# DO NOT have other things unindented BETWEEN if and else; comments are ok
# else needs to follow an if, cannot be by itself (dangling else)

print( 'all done' )