You may make a copy of a worksheet and complete this activity, or simply type your answers in any text editor.
You may work alone or with 3-4 students in this course (max size=5).
Given the following relations and schemas, write SQL queries to solve the problems.
Movies (title, year, length, genre, studioName, producerCert) starsIn (movieTitle, movieYear, starName, salary) MovieStar (name, address, gender, birthdate) MovieExec (name, address, producerCert, netWorth) Studio (name, address)
SELECT address AS Studio_Address FROM Studio WHERE name = "MGM";
SELECT COUNT(*) FROM Movies WHERE studioName <> "MGM";
   SELECT  starName
   FROM    StarsIn
   WHERE   movieYear = 2023 OR 
           movieTitle LIKE "%Love%";
However, the above query will also return words that have the substring Love e.g. Lover. 
Below query will only return movies that have title containing the word Love.   
   SELECT  starName
   FROM    StarsIn
   WHERE   movieYear = 2023 OR 
           movieTitle LIKE "Love %" OR 
           movieTitle LIKE "% Love %" OR 
           movieTitle LIKE "% Love" OR movieTitle = "Love";         
          SELECT name FROM MovieExec WHERE 5000000 <= netWorth AND netWorth <= 10000000; Another solution: SELECT name FROM MovieExec WHERE netWorth BETWEEN 5000000 AND 10000000;
SELECT name AS Star_Name FROM movieStar WHERE gender = "F" OR address LIKE '%Malibu%'; // '% Malibu %' ?
   SELECT  M.name AS starName
   FROM    MovieStar M,
           StarsIn S
   WHERE   M.name = S.starName AND 
           S.movieTitle = "Star Wars" AND 
           M.gender = "M";    
           Assuming the same movie title may be made in multiple years 
   SELECT  S.starName AS starName 
   FROM    Movies M, 
           starsIn S 
   WHERE   M.title = S.movieTitle AND 
           M.year = S.movieYear AND 
           M.year = 2023 AND 
           M.studioName = 'MGM'    
             SELECT DISTINCT MovieStar.address 
   FROM   MovieStar, MovieExec 
   WHERE  MovieStar.address LIKE "%Malibu%" AND 
          MovieStar.address = MovieExec.address
   
Another possible solution: 
   (SELECT address
   FROM    MovieStar
   WHERE   address LIKE '%Malibu%')  
   INTERSECT
   (SELECT address
   FROM    MovieExec
   WHERE   address LIKE '%Malibu%')                 
          
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